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2(x^2-6)=82
We move all terms to the left:
2(x^2-6)-(82)=0
We multiply parentheses
2x^2-12-82=0
We add all the numbers together, and all the variables
2x^2-94=0
a = 2; b = 0; c = -94;
Δ = b2-4ac
Δ = 02-4·2·(-94)
Δ = 752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{752}=\sqrt{16*47}=\sqrt{16}*\sqrt{47}=4\sqrt{47}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{47}}{2*2}=\frac{0-4\sqrt{47}}{4} =-\frac{4\sqrt{47}}{4} =-\sqrt{47} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{47}}{2*2}=\frac{0+4\sqrt{47}}{4} =\frac{4\sqrt{47}}{4} =\sqrt{47} $
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